# First Quiz: Finding the vertex, X and Y-intercepts of a quadratic equation

## First Quiz: Finding the vertex, X and Y-intercepts of a quadratic equation

### X,Y Intercepts

#### Finding the y-intercept

Let Y be or equal 0 then,

$Y\quad =\quad (0)^{ 2 }\quad -\quad 6(0)$

$=\quad 0$

#### Finding the x-intercept

Let x be or equal 0 then,

$0\quad =\quad x(x-6)$

$x\quad =\quad 0,\quad 6$

### Finding the vertex

#### Finding the vertex of X

$x\quad =\quad -\frac { b }{ 2a }$

$x\quad =\quad -\frac { (-6) }{ (2) }$

$x\quad =\quad \frac { 6 }{ 2 } \quad =\quad 3$

#### Finding the vertex of Y

$y\quad =\quad -\frac { { b }^{ 2 }-4ac }{ 4a }$

$y\quad =\quad -\frac { { b }^{ 2 }-4ac }{ 4a } \quad =\quad \frac { 36\quad -4(1)(0) }{ 4 } \quad =\quad -9$

Vertex = (3, -9)