First Quiz: Finding the vertex, X and Y-intercepts of a quadratic equation

First Quiz: Finding the vertex, X and Y-intercepts of a quadratic equation

 

Question :     Y\quad =\quad { x }^{ 2 }\quad -\quad 6x

X,Y Intercepts

Finding the y-intercept

Let Y be or equal 0 then,

Y\quad =\quad (0)^{ 2 }\quad -\quad 6(0)

=\quad 0

 

Finding the x-intercept

Let x be or equal 0 then,

0\quad =\quad x(x-6)

x\quad =\quad 0,\quad 6

 

Finding the vertex

Finding the vertex of X

x\quad =\quad -\frac { b }{ 2a }

x\quad =\quad -\frac { (-6) }{ (2) }

x\quad =\quad \frac { 6 }{ 2 } \quad =\quad 3

Finding the vertex of Y

y\quad =\quad -\frac { { b }^{ 2 }-4ac }{ 4a }

y\quad =\quad -\frac { { b }^{ 2 }-4ac }{ 4a } \quad =\quad \frac { 36\quad -4(1)(0) }{ 4 } \quad =\quad -9

Vertex = (3, -9)

 

Graphing

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